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Match List I with List II {:("List I",...

Match List I with List II
`{:("List I"," ""ListII"),("(Monomer unit)"," "("Polymer")),("(a) Carprolactum"," ""(i) Natural ruber"),("(b)2-Chloro-1-,3-butadience"," ""(ii) Buna-N"),("(c) Isoperene"," ""(iii) Nylon 6"),("(d) Acrylonitrile"," ""(iv) Neoprene"):}`
Chosse the correct answer from the options given below

A

`(a)rarr(iv),(b)rarr(iii),(c)rarr(ii),(d)rarr(i)`

B

`(a)rarr(ii),(b)rarr(i),(c)rarr(iv),drarr(iii)`

C

`(a)rarr(iii),(b)rarr(iv),(c)rarr(i),(d)rarr(ii)`

D

`(a)rarr(i),(b)rarr(ii),(c)rarr(iii),(d)rarr(iv)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of matching the monomers from List I with their corresponding polymers from List II, we will analyze each monomer and identify the polymer it forms. ### Step 1: Identify the Monomer and its Corresponding Polymer 1. **Carprolactam**: - Carprolactam is the monomer for Nylon 6. - **Match**: (a) Carprolactam → (iii) Nylon 6 2. **2-Chloro-1,3-butadiene**: - This monomer is known as chloroprene, which is used to make Neoprene. - **Match**: (b) 2-Chloro-1,3-butadiene → (iv) Neoprene 3. **Isoprene**: - Isoprene is the monomer for Natural Rubber. - **Match**: (c) Isoprene → (i) Natural Rubber 4. **Acrylonitrile**: - Acrylonitrile is used along with butadiene to form Buna-N. - **Match**: (d) Acrylonitrile → (ii) Buna-N ### Summary of Matches: - (a) Carprolactam → (iii) Nylon 6 - (b) 2-Chloro-1,3-butadiene → (iv) Neoprene - (c) Isoprene → (i) Natural Rubber - (d) Acrylonitrile → (ii) Buna-N ### Final Answer: - (a) → (iii) - (b) → (iv) - (c) → (i) - (d) → (ii)
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