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A solid sphere of radius R gravitationa...

A solid sphere of radius R gravitationally attracts a particle placed at 3R form its centre with a force `F_(1)`. Now a spherical cavity of radius `((R)/(2))` is made in the sphere (as shown in figure) and the force becomes `F_(2)` The value of `F_(1) : F_(2)` is:

A

`25:36`

B

`36:25`

C

`50:41`

D

`41:50`

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The correct Answer is:
C
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