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Given below are two statements : Stat...

Given below are two statements :
Statement I : In a diatomic molecule, the rotational energy at a given temperature obeys Maxwell's distribution.
Statement II : In a diatomic molecule, the rotational energy at a given temperature equals the translational kinetic energy for each molecule.
In the light of the above statements, choose the correct answer from the options given below :

A

Statement I is false but Statement II is true.

B

Both Statement I and Statement II are false.

C

Both Statement I and Statement II are true.

D

Statement I is true but Statement II is false.

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze the two statements provided regarding diatomic molecules and their energy distributions. ### Step-by-Step Solution: 1. **Understanding Statement I**: - The first statement claims that in a diatomic molecule, the rotational energy at a given temperature obeys Maxwell's distribution. - Maxwell's distribution describes the distribution of speeds (or energies) of particles in a gas at thermal equilibrium. - For diatomic molecules, which have rotational degrees of freedom, the rotational kinetic energy indeed follows this distribution. - **Conclusion**: Statement I is **True**. 2. **Understanding Statement II**: - The second statement claims that in a diatomic molecule, the rotational energy at a given temperature equals the translational kinetic energy for each molecule. - For a diatomic gas, the degrees of freedom are as follows: - Translational degrees of freedom: 3 (movement in x, y, and z directions) - Rotational degrees of freedom: 2 (rotation about two axes perpendicular to the molecular axis) - The average translational kinetic energy for a diatomic gas is given by: \[ \text{Translational K.E.} = \frac{3}{2} kT \] - The average rotational kinetic energy for a diatomic gas is given by: \[ \text{Rotational K.E.} = \frac{2}{2} kT = kT \] - Comparing these, we see that: - Translational K.E. = \(\frac{3}{2} kT\) - Rotational K.E. = \(kT\) - Therefore, the translational kinetic energy is greater than the rotational kinetic energy. - **Conclusion**: Statement II is **False**. 3. **Final Evaluation**: - Since Statement I is True and Statement II is False, the correct answer based on the evaluation of the statements is that only Statement I is correct. ### Summary: - **Statement I**: True - **Statement II**: False
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