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A tuning fork A of unknown frequency pro...

A tuning fork A of unknown frequency produces 5 beats/s with a fork of known frequency 340 Hz. When fork A is filed, the beat frequency decreases to 2 beats/s. What is the frequency of fork A ?

A

342 Hz

B

345 Hz

C

335 Hz

D

338 Hz

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The correct Answer is:
To solve the problem, we need to find the frequency of tuning fork A (denoted as \( F_A \)) based on the information provided about the beat frequencies with a known tuning fork of frequency \( F_B = 340 \) Hz. ### Step-by-Step Solution: 1. **Understanding Beat Frequency**: The beat frequency is given by the absolute difference between the frequencies of two tuning forks. Therefore, the beat frequency \( f_b \) can be expressed as: \[ f_b = |F_A - F_B| \] 2. **Initial Condition**: We are told that tuning fork A produces 5 beats per second with fork B (340 Hz). This gives us two possible equations: \[ |F_A - 340| = 5 \] This can lead to two scenarios: - \( F_A - 340 = 5 \) → \( F_A = 345 \) Hz - \( 340 - F_A = 5 \) → \( F_A = 335 \) Hz 3. **Filing the Fork**: When fork A is filed, its frequency increases. We denote the new frequency of fork A after filing as \( F_A' \). Since filing increases the frequency, we have: \[ F_A' > F_A \] 4. **New Beat Frequency**: After filing, the beat frequency decreases to 2 beats per second. Thus, we have: \[ |F_A' - 340| = 2 \] This leads to two new scenarios: - \( F_A' - 340 = 2 \) → \( F_A' = 342 \) Hz - \( 340 - F_A' = 2 \) → \( F_A' = 338 \) Hz 5. **Analyzing the Scenarios**: - If \( F_A = 345 \) Hz (from the first scenario), then after filing, \( F_A' \) would be greater than 345 Hz. This means \( F_A' \) cannot be 342 Hz or 338 Hz, as both are less than 345 Hz. - If \( F_A = 335 \) Hz, then after filing, \( F_A' \) would be greater than 335 Hz. This means \( F_A' \) could be 342 Hz or 338 Hz. 6. **Finding the Correct Frequency**: Since \( F_A' \) must be greater than 335 Hz and can be either 342 Hz or 338 Hz, the only valid frequency for \( F_A \) that satisfies all conditions is: \[ F_A = 335 \text{ Hz} \] ### Final Answer: The frequency of tuning fork A is \( 335 \) Hz.
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