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A radioactive sample is undergoing alpha...

A radioactive sample is undergoing `alpha` - decay. At time `t_1`, its activity is A & at A another time `t_2`, the activity is `A/5`. What is the average life time for the sample

A

`(ln5)/(t_(2)-t_(1))`

B

`(t_(1)-t_(2))/(ln5)`

C

`(t_(2)-t_(1))/(ln5)`

D

`(ln(t_(2)+t_(1)))/(2)`

Text Solution

Verified by Experts

The correct Answer is:
C
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