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When light of wavelength 248 nm falls on...

When light of wavelength 248 nm falls on a metal of threshold energy 3.0 eV, the de-Broglie wavelength of emitted electrons is `"_________"Å` (Round off to the Nearest Integer).
[Use `: sqrt3 = 1.73 , h - 6.63 xx 10 ^(-34) Js`
`m _(c ) = 9.1 xx 10 ^(-31) kg , c =3.0 xx 10 ^(8) ms ^(-1) ,1eV = 1. 6 xx 10 ^(-19))]`

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