A particle slides down a smooth inclined plane of elevation `theta` fixed in an elevator going up with an acceleration`a_0`. The base of the incline has a length L.Find the time taken by the particle to reach the bottom.

Options

A. `sqrt((2L)/((g + a) sin theta)`
B. `sqrt((2L)/((g - a) sin theta)`
C. `sqrt((2L)/( a sin theta)`
D. `sqrt((2L)/(g sin theta)`

Answer

A

Explanation

Acceleration of block with respect to lift . Pseudo force `= `(downward)

`a_(r) = (m ( g + a) sin theta)/(m) = (g + a) sin theta`
`S = (1)/(2) a_(r) t^(2)`
`t= sqrt((2S)/(a_(r))) = sqrt ((2L)/((g + a) sin theta))`