In figure two identical particals each of mass `m` are tied together with an inextensible string. This is pulled at its centre wwith a constant force `F`. If the whole system lines on a smooth horizontal plane, then the aceleration of each partical towards each other is

Options

A. `(a)sqrt(3)/(2) (F)/(m)`
B. `(b)(1)/(2 sqrt 3) (F)/(m)`
C. `(c)(2)/sqrt(3) (F)/(m)`
D. `(d)sqrt(3) (F)/(m)`

Answer

B

Explanation

At point `P`.

`F = 2T cos 30^(@)`
`T = (F)/sqrt(3)`
Acceleration of partical towards each other
`= ("component of towards each other partical")/(m)`
`= (T cos 60^(@))/(m) = ((F//sqrt3) (1//2))/(m) = (F)/(2sqrt3 m)`