A body of mass `10 kg` lies on a rough inclined plane of inclination `theta = sin^(-1) ((3)/(5))` with the horizontal. When the force of `30 N`is applied on the block parallel to and upward the plane, the total force by the plane on the block is nearly along

Options

A. `(a)OA`
B. `(b)OB`
C. `(c)OC`
D. `(d)OD`

Answer

A

Explanation

`mg sin theta = (10) (10) (3//5) = 60 N`
This `60 N gt 30 N`.Therefore friction force `f` will act in upward direction

`F = sqrt(N^(2) + f^(2)) =` not force by plane on the block