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A man of mass m stands on a platform of ...

A man of mass `m` stands on a platform of equal mass `m` and pulls himself by two ropes passing over pulleys as shown in figure.If he pulls each rop with a force equal to half his weight ,his upwards acceleration would be

A

`(a)(g)/(2)`

B

`(b)(g)/(4)`

C

`(c)g`

D

(d)zero

Text Solution

Verified by Experts

The correct Answer is:
D
Total upward force `= 4 ((m g)/(2)) = 2 m g`

Total downward force`= (m + m) g = 2 m g
`:.` Net force`= 0`
`F = (mg)/(2)`
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