A ball of mass `1 kg` hangs in equilibrium from two string `OA` and `OB` as show in figure. What are the tension in string `OA` and `OB`? `(Take g= 10 m//s^(2))`

Explanation

Verious forces acting on the ball on are as shown in figure .The three concerrent forces are in equibrium.Using Lam's theorem.

`(T_(1))/(sin 150^(@)) = (T_(2))/(sin 120^(@)) =(10)/(sin 90^(@))`
or `(T_(1))/(sin 30^(@)) = (T_(2))/(sin 60^(@)) =(10)/(1)`
and `T_(1) = 10 sin 30^(@)= 10 xx 0.5`
`= 5 N` and `T_(2) = 10 sin 60^(@)= 10 xx (sqrt3)/(2)`
`= 5 sqrt(3) N`