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Two beads of equal masses m are attached...

Two beads of equal masses `m` are attached by a string of length `sqrt2a` and are free to move in a smooth circular ring lying in a vertical plane as shown in figure. Here a is the radius of the ring. Find the tension and acceleration of `B` just offer the heads are released to move.

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For `A` `T cos 45^(@) = ma`
`T = sqrt2 ma` …(i)
For `B` `m g - T cos 45^(@) = ma`
:. `M g - ma= ma` or `a = (g)/(2)`
Substituting in Eq. (i) we get `T = (mg)/(sqrt2)`
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