Two unequal masses of `1kg` and `2kg` are connected by a string going over a clamed light smooth pulley as shown in figure . The system is released from rest .The larger mass is stopped for a moment `1.0 s` after the system is set in motion.Find the time elapsed before the string is tight again.

Explanation

`a = ("Net pulling force")/("Total mass")`
`= (2 g - (1) g)/(2 + 1)`
`= (g)/(3) = (10)/(3) m //s^(2)`
After `1 s`
`v = at =(10)/(3) m//s`
At this string slacks `(T = 0)`

String is again tight when ,
:. `(10)/(3) t - (1)/(2) g t^(2) = (1)/(2) g t^(2)` `(g = m//s^(2))`
On solving , we get,
`t = (1)/(3) s`