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In the adjoining figure a wedge is fixed...

In the adjoining figure a wedge is fixed to an elevator moving upwards with an acceleration `a`. A block of mass `m` is placed over the wedge.Find the acceleration of the block with respect to wedge. Neglect friction

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Since acceleration of block `w.r.t.` wedge (an accelerating or non -inference) is to br find out.

`FBD` of block `w.r.t.` is shown in figure.The acceleration would had been `g sin theta` (down the plane) if the lift were stationary or when only weight (i.e. m g) act downwards.
Here downward force is `m (g + a)`.
:. Acceleration of the block (of course `w.r.t.` wedge) will be `(g + a) sin theta` the plane.
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