For the arrangement shown in the figure the coefficient of friction between the two blocks is `mu`. If both the blocks are identical and moving ,then the acceleration of each block is

Options

A. `(F)/(2 m) - 2 mu g`
B. `(F)/(2 m)`
C. `(F)/(2 m) - mu g`
D. `zero`

Answer

C

Explanation

`T - mu mg = ma`

`:. T - mu mg = ma`
`F - T - mu mg = ma`
`:.F - mu mg - ma - mu mg = ma`
or `a = (f)/(2 m) - mu mg`