The minimum value of `mu` between the two blocks for no slipping is

Options

A. `(F)/(2mg)`
B. `(F)/(3 mg)`
C. `(2 F)/(3 mg)`
D. `(4 F)/(3 mg)`

Answer

C

Explanation

If they do slip, then not force on system `= F`
`:.` Acceleration of system `a = (F)/(3m)`
`T = F`
`FBD` of `m F - mu mg = ma = (F)/(3)`

`:.mu mg = (2 F)/(3)` or `mu = (2 F)/(3 mg)`