A liquid takes 5 minutes to cool from `80^@C` to` 50^@C` . How much time will it take to cool from `60^@C` to `30^@C`? The temperature of surroundings is `20^@C`.

Explanation

To solve the problem of how long it will take for a liquid to cool from 60°C to 30°C, given that it takes 5 minutes to cool from 80°C to 50°C, we can use Newton's Law of Cooling. Here’s a step-by-step solution:

### Step 1: Identify the given data
- Initial temperature (T1) = 80°C
- Final temperature (T2) = 50°C
- Time taken (t1) = 5 minutes
- Surrounding temperature (T0) = 20°C

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