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Three photo diodes D1, D2, and D3 are ma...

Three photo diodes `D_1, D_2, and D_3` are made of semiconductors having band gap of 2.5 eV, 2 eV and 3 eV, respectively. Which one will be able to detect light of wavelength 6000 Å ?

Text Solution

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The correct Answer is:
A
Energy of incident light
` E ("in" eV ) = 12375/ (lambda ("in" Å )) `
` E = 12375 / 6000 eV `
or ` E = 2.06 eV `
For the incident radiation to be detected by the photodiode energy of incident radiation should be greater than the band gap . This is true only for ` D_2 ` . Therefore only `D_2` will detect this radiation .
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