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A rotating wheel changes angular speed f...

A rotating wheel changes angular speed from 1800 rpm to 3000 rpm in 20 s. What is the angular acceleration assuming to be uniform?

A

`60 pi rad s^(-2)`

B

`90 pi rad s^(-2)`

C

`2 pi rad s^(-2)`

D

`40 pi rad s^(-2)`

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The correct Answer is:
To find the angular acceleration of a rotating wheel that changes its angular speed from 1800 rpm to 3000 rpm in 20 seconds, we can follow these steps: ### Step 1: Identify the given values - Initial angular speed (\( \omega_0 \)) = 1800 rpm - Final angular speed (\( \omega \)) = 3000 rpm - Time interval (\( t \)) = 20 seconds ### Step 2: Convert angular speeds from rpm to rps Since the angular speeds are given in revolutions per minute (rpm) and the time is in seconds, we need to convert the angular speeds to revolutions per second (rps). \[ \omega_0 = \frac{1800 \text{ rpm}}{60} = 30 \text{ rps} \] \[ \omega = \frac{3000 \text{ rpm}}{60} = 50 \text{ rps} \] ### Step 3: Use the formula for angular acceleration The formula relating angular acceleration (\( \alpha \)), initial angular speed (\( \omega_0 \)), final angular speed (\( \omega \)), and time (\( t \)) is: \[ \omega = \omega_0 + \alpha t \] ### Step 4: Rearrange the formula to solve for angular acceleration (\( \alpha \)) Rearranging the formula gives us: \[ \alpha = \frac{\omega - \omega_0}{t} \] ### Step 5: Substitute the values into the equation Now, substituting the values we have: \[ \alpha = \frac{50 \text{ rps} - 30 \text{ rps}}{20 \text{ s}} = \frac{20 \text{ rps}}{20 \text{ s}} = 1 \text{ rps}^2 \] ### Step 6: Convert angular acceleration to radians per second squared Since the problem asks for the answer in radians per second squared, we need to convert revolutions per second squared to radians per second squared. We know that: \[ 1 \text{ revolution} = 2\pi \text{ radians} \] Thus, we can convert: \[ \alpha = 1 \text{ rps}^2 \times 2\pi = 2\pi \text{ rad/s}^2 \] ### Final Answer Therefore, the angular acceleration is: \[ \alpha = 2\pi \text{ rad/s}^2 \] ### Conclusion Looking at the options provided, the correct answer is option 3: \( 2\pi \) rad/s². ---

To find the angular acceleration of a rotating wheel that changes its angular speed from 1800 rpm to 3000 rpm in 20 seconds, we can follow these steps: ### Step 1: Identify the given values - Initial angular speed (\( \omega_0 \)) = 1800 rpm - Final angular speed (\( \omega \)) = 3000 rpm - Time interval (\( t \)) = 20 seconds ### Step 2: Convert angular speeds from rpm to rps ...
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DC PANDEY ENGLISH-ROTATION-Check point 9.1
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  2. A wheel rotates with a constant angular velocity of 300 rpm. The angle...

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  3. A motor is rotating at a constant angular velocity of 500 rpm. The ang...

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  5. A rotating wheel changes angular speed from 1800 rpm to 3000 rpm in 20...

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  6. A body rotating with uniform angular acceleration covers 100 pi (radia...

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  7. The angular velocity of a wheel increases from 100 to 300 in 10 s. Th...

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  8. A wheel has angular acceleration of 3.0 rad//s^2 and an initial angula...

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  9. A body rotates about a fixed axis with an angular acceleration of 3 ra...

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  10. A wheel which is initially at rest is subjected to a constant angular ...

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  11. Analogue of mass in rotational motion is

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  12. Moment of inertia of a body depends upon

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