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What is the moment of inertia of a solid...

What is the moment of inertia of a solid sphere of density `rho` and radius R about its diameter ?

A

`(105)/(176) R^(5) rho`

B

`(176)/(105) R^(5) rho`

C

`(105)/(176) R^(2) rho`

D

`(176)/(105) R^(2) rho`

Text Solution

AI Generated Solution

The correct Answer is:
To find the moment of inertia of a solid sphere of density \( \rho \) and radius \( R \) about its diameter, we can follow these steps: ### Step 1: Understand the Moment of Inertia The moment of inertia \( I \) about an axis is a measure of how difficult it is to change the rotational motion of an object about that axis. For a solid sphere, we need to find the moment of inertia about its diameter. ### Step 2: Use the Formula for Moment of Inertia The moment of inertia about the center of mass (CM) for a solid sphere is given by the formula: \[ I_{CM} = \frac{2}{5} M R^2 \] where \( M \) is the mass of the sphere and \( R \) is its radius. ### Step 3: Calculate the Mass of the Sphere The mass \( M \) of the sphere can be calculated using its volume and density: \[ M = \text{Volume} \times \text{Density} = V \times \rho \] The volume \( V \) of a solid sphere is given by: \[ V = \frac{4}{3} \pi R^3 \] Thus, the mass becomes: \[ M = \frac{4}{3} \pi R^3 \rho \] ### Step 4: Substitute Mass into the Moment of Inertia Formula Now, substitute the expression for mass \( M \) into the moment of inertia formula: \[ I_{AB} = I_{CM} = \frac{2}{5} \left(\frac{4}{3} \pi R^3 \rho\right) R^2 \] This simplifies to: \[ I_{AB} = \frac{2}{5} \times \frac{4}{3} \pi R^5 \rho \] ### Step 5: Simplify the Expression Now, simplify the expression: \[ I_{AB} = \frac{8}{15} \pi R^5 \rho \] ### Step 6: Substitute \(\pi\) for Approximation For approximation, we can use \( \pi \approx \frac{22}{7} \): \[ I_{AB} = \frac{8}{15} \times \frac{22}{7} R^5 \rho \] ### Step 7: Final Calculation Now, calculate the final expression: \[ I_{AB} = \frac{176}{105} R^5 \rho \] ### Conclusion Thus, the moment of inertia of the solid sphere about its diameter is: \[ I_{AB} = \frac{176}{105} R^5 \rho \] ### Answer The correct option is: \[ \text{Option 2: } \frac{176}{105} R^5 \rho \] ---

To find the moment of inertia of a solid sphere of density \( \rho \) and radius \( R \) about its diameter, we can follow these steps: ### Step 1: Understand the Moment of Inertia The moment of inertia \( I \) about an axis is a measure of how difficult it is to change the rotational motion of an object about that axis. For a solid sphere, we need to find the moment of inertia about its diameter. ### Step 2: Use the Formula for Moment of Inertia The moment of inertia about the center of mass (CM) for a solid sphere is given by the formula: \[ ...
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DC PANDEY ENGLISH-ROTATION-Check point 9.1
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