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Assertion An induced emf of 2 V is devel...

Assertion An induced emf of 2 V is developed in a circular loop, if current in the loop is changed at a rate of 4 `As^(-1)` .IF 4 A of current is passed through this loop, then flux linked with this coil will be 2 Wb.
Reason Flux linked with the coil is
`|phi|=|(e)/(di//dt)|i`

A

If both Assertion and Reason are corrent and Reason is the corrent explanation of Assertion.

B

If both Assertion and Reason are correct but Reason is not the correct explanation of Assertion.

C

If Assertion is true but Reason is false.

D

If Assertion is false but Reason is ture.

Text Solution

AI Generated Solution

The correct Answer is:
To solve the given problem, we will analyze both the assertion and the reason step by step. ### Step 1: Understanding the Given Information We are provided with: - An induced emf (E) of 2 V. - A rate of change of current (di/dt) of 4 A/s. - A current (I) of 4 A flowing through the loop. ### Step 2: Using the Formula for Induced EMF The induced emf in a coil can be expressed using the formula: \[ E = L \frac{di}{dt} \] where \( L \) is the inductance of the coil. ### Step 3: Rearranging the Formula to Find Inductance From the formula above, we can rearrange it to find the inductance \( L \): \[ L = \frac{E}{\frac{di}{dt}} \] Substituting the known values: \[ L = \frac{2 \, \text{V}}{4 \, \text{A/s}} = 0.5 \, \text{H} \] ### Step 4: Finding the Magnetic Flux Linked with the Coil The magnetic flux \( \Phi \) linked with the coil can be expressed as: \[ \Phi = L \cdot I \] Substituting the values we have: \[ \Phi = 0.5 \, \text{H} \cdot 4 \, \text{A} = 2 \, \text{Wb} \] ### Step 5: Conclusion The assertion states that the flux linked with the coil will be 2 Wb, which we have calculated to be true. Therefore, the assertion is correct. ### Step 6: Validating the Reason The reason provided states that: \[ |\Phi| = \left|\frac{E}{\frac{di}{dt}}\right| I \] This is consistent with our calculations since we derived that: \[ \Phi = L \cdot I \] and \( L \) was calculated as \( \frac{E}{\frac{di}{dt}} \). Thus, the reason is also correct. ### Final Answer Both the assertion and the reason are true, and the reason correctly explains the assertion. ---

To solve the given problem, we will analyze both the assertion and the reason step by step. ### Step 1: Understanding the Given Information We are provided with: - An induced emf (E) of 2 V. - A rate of change of current (di/dt) of 4 A/s. - A current (I) of 4 A flowing through the loop. ...
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