Assertion If current passing through a circular loop is doubled, then magnetic flux linked with the circular loop will also become two times.
Reason No flux will link through the coil by its own current.

Options

A. If both Assertion and Reason are corrent and Reason is the corrent explanation of Assertion.
B. If both Assertion and Reason are correct but Reason is not the correct explanation of Assertion.
C. If Assertion is true but Reason is false.
D. If Assertion is false but Reason is ture.

Explanation

To solve the question, we need to analyze the assertion and the reason given.

**Assertion:** If current passing through a circular loop is doubled, then magnetic flux linked with the circular loop will also become two times.

**Reason:** No flux will link through the coil by its own current.

### Step-by-Step Solution:

1. **Understanding Magnetic Flux:**
Magnetic flux (Φ) linked with a loop is defined as the product of the magnetic field (B) and the area (A) through which the magnetic field lines pass, and it is also dependent on the angle (θ) between the magnetic field lines and the normal to the surface of the loop.
\[ \Phi = B \cdot A \cdot \cos(\theta) \]

2. **Relation Between Current and Magnetic Field:**
For a circular loop carrying current (I), the magnetic field (B) at the center of the loop is given by:
\[ B = \frac{\mu_0 I}{2R} \]
where \( \mu_0 \) is the permeability of free space and \( R \) is the radius of the loop.

3. **Effect of Doubling the Current:**
If the current (I) is doubled (let's say it becomes 2I), the new magnetic field (B') at the center of the loop becomes:
\[ B' = \frac{\mu_0 (2I)}{2R} = \frac{\mu_0 I}{R} \]
This shows that the magnetic field at the center of the loop also doubles.

4. **Calculating New Magnetic Flux:**
The magnetic flux linked with the loop when the current is doubled can be calculated as:
\[ \Phi' = B' \cdot A = \left(\frac{\mu_0 I}{R}\right) \cdot A \]
Since the area (A) of the loop remains constant, the new magnetic flux (Φ') is:
\[ \Phi' = 2 \cdot \left(\frac{\mu_0 I}{2R} \cdot A\right) = 2\Phi \]
This indicates that if the current is doubled, the magnetic flux linked with the loop also becomes double.

5. **Evaluating the Reason:**
The reason states that no flux will link through the coil by its own current. However, this is incorrect because the current flowing through the loop does indeed create a magnetic field, which in turn links magnetic flux with the loop itself.

6. **Conclusion:**
Therefore, the assertion is true, and the reason is false. The correct answer is that the assertion is true, but the reason is false.

### Final Answer:
Assertion is true, Reason is false.