A carbon resistor of `(47 +- 4.7) k Omega` is to be marked with rings of different colours for its identification. The colour code sequence will be

Options

A. Yellow- Green-Violet-Gold
B. Yellow-Violet-Orange-Silver
C. Violet-Yellow-Orange-Silver
D. Green-Orange-Violet-Gold

Explanation

To determine the color code for the carbon resistor with a resistance of \( (47 \pm 4.7) \, k\Omega \), we will follow these steps:

### Step 1: Identify the nominal resistance value
The nominal resistance value is given as \( 47 \, k\Omega \).

### Step 2: Express the resistance in standard form
We can express the resistance in standard form:
\[ R = 47 \times 10^3 \, \Omega \]

### Step 3: Determine the significant figures
The first two digits of the resistance value \( 47 \) will be used to determine the first two color bands.

### Step 4: Assign colors to the first two digits
Using the color code:
- The first digit \( 4 \) corresponds to **Yellow**.
- The second digit \( 7 \) corresponds to **Violet**.

### Step 5: Determine the multiplier
The resistance is multiplied by \( 10^3 \). The color for \( 10^3 \) corresponds to **Orange**.

### Step 6: Determine the tolerance
The tolerance is given as \( \pm 10\% \). According to the color code, a tolerance of \( 10\% \) is represented by **Silver**.

### Step 7: Combine the colors for the color code
The complete color code for the resistor is:
- First band: Yellow
- Second band: Violet
- Third band: Orange
- Fourth band: Silver

### Final Answer
Thus, the color code sequence for the resistor is **Yellow, Violet, Orange, Silver**.

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