Current senstivity of moving coil galvanometer is `5 "div"//mA` and its voltage senstivity (angular deflection per unit voltage applied) is `20 "div"//V`. The resistance of the galvanometer is

Options

A. `250 Ohm
B. `25 Ohm
C. `40 Ohm`
D. `500 Ohm

Explanation

To find the resistance of the moving coil galvanometer, we can use the relationship between current sensitivity (Si), voltage sensitivity (Sv), and the resistance of the galvanometer (Rg).

### Step-by-Step Solution:

1. **Identify Given Values:**
- Current sensitivity, \( Si = 5 \, \text{div/mA} = 5 \times 10^3 \, \text{div/A} \)
- Voltage sensitivity, \( Sv = 20 \, \text{div/V} \)

2. **Understand the Relationship:**
- The relationship between current sensitivity, voltage sensitivity, and resistance of the galvanometer is given by:
\[ Rg = \frac{Si}{Sv} \]

3. **Substitute the Values:**
- Substitute the values of \( Si \) and \( Sv \) into the equation:
\[ Rg = \frac{5 \times 10^3 \, \text{div/A}}{20 \, \text{div/V}} \]

4. **Calculate the Resistance:**
- Perform the division:
\[ Rg = \frac{5 \times 10^3}{20} = 250 \, \Omega \]

5. **Conclusion:**
- The resistance of the galvanometer is \( Rg = 250 \, \Omega \).

### Final Answer:
The resistance of the galvanometer is \( 250 \, \Omega \).

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