In a series `C-R` circuit shown in figureure, the applied voltage is `10 V` and the voltage across capacitor is found to`8 V`. The voltage across `R`, and the phase difference between current and the applied voltage will respectively be
.

Options

A. 6V, `tan^(-1)(4/3)`
B. `3V, tan^(-1)(3/4)`
C. `6V, tan^(-1)(5/3)`
D. None of these

Answer

A

Explanation

We know that, for series R-C circuit
`V^(2)=V_(C)^(2)+V_(R)^(2)`

`100 = 64 + V_(R)^(2) =36 rArr V_(R) = sqrt(36) = 6V`
Also, `tanphi = V_(C)/V_(R) rArr tanphi = 8/6`
`tanphi = 4/3`
`therefore phi=tan^(-1)(4/3)`