An atomic power nuclear reactor can deliver `300 MW`. The energy released due to fission of each nucleus of uranium atom `U^238` is `170 MeV`. The number of uranium atoms fissioned per hour will be.

Options

A. `30 xx 10^(25)`
B. `4 xx 10^(22)`
C. `10 xx 10^(2)`
D. `5 xx 10^(15)`

Answer

B

Explanation

b) Power = energy/time = `300 xx 10^(8)J//s`
energy released due to fission
`=170 MeV = 170 xx 10^(6)xx 1.6 xx 10^(-19)`
`=27.2 xx 10^(-12)` J
Number of atoms fissioned per second.
`=(3 xx 10^(8))/(27.2 xx 10^(12)) = (3 xx 10^(20))/(27.2)`
Number of atoms fissioned per hour
`=(3 xx 10^(20)xx 3600)/(27.2)=(3 xx 36)/(27.2) xx 10^(22) = 4 xx 10^(22)`m