Home
Class 12
PHYSICS
If an electron is moving with velocity v...

If an electron is moving with velocity v produces a magnetic field `vecB`, then

A

`B propto v propto 1/r`

B

`B propto v propto 1/r^(2)`

C

`B propto v^(2) propto 1/r`

D

`B propto v^(2) propto 1/r^(2)`

Text Solution

Verified by Experts

The correct Answer is:
B

`therefore` Magnetic field at center.
`B=(mu_(0)I)/(2r)`
Where, `I=e/t`
or `i= e/((2pir)/v) = (ev)/(2pir)`
Hence, `B=(mu_(0))/(2r)((ev)/(2pir)) = (mu_(0)ev)/(4pir^(2))`
or `B propto v/I^(2)`
Promotional Banner

Topper's Solved these Questions

  • SOLVED PAPERS 2018

    DC PANDEY ENGLISH|Exercise Assertion and Reasons|10 Videos
  • SOLVED PAPER 2017

    DC PANDEY ENGLISH|Exercise Solved papers 2017(JIPMER)|32 Videos
  • WAVE OPTICS

    DC PANDEY ENGLISH|Exercise For JEE Advanced E. Integer Type Questions|13 Videos

Similar Questions

Explore conceptually related problems

Biot-Savart law indicates that the moving electrons (velocity vecv ) produce a magnetic field vecB such that

Biot-Savart law indicates that the moving electrons (velocity vecv ) produce a magnetic field vecB such that

Biot-Savart law indicates that the moving electrons (velocity vecv ) produce a magnetic field vecB such that

Write an expression in a vector form for the Lorentz magnetic force vecF on a charge Q moving with velocity vecV in a magnetic field vecB . What is the direction of the magnetic force?

Answer the following: (a) Write the expression for the force vec(F) acting on a particle of mass m and charge q moving with velocity vecV in a magnetic field vecB . Under what conditions will it move in (i) a circular path and (ii) a helical path ? (b) Show that the kinetic energy of the particle moving a magnetic field remains constant.

If an electron is moving with velocity v in an orbit of radius r then the equivalent magnetic field at the centre will be:

The potential difference across the ends of the rod moving with velocity v perpendicular magnetic field is

Define one tesla using the expression fo the magnetic force acting on a particle of charge .q. moving with velocity vec(v) in a magnetic field vec(B) .

(A) : An electron moving with uniform velocity enters uniform magnetic field perpendicularly and then a uniform electric field in the same direction. Nature of paths followed by electron in both the fields will be same. (R) : The force applied by magnetic and electric field on electron are in the same direction.

(a) Write the expression for the magnetic force acting on a k charged particle moving with velocity v in the presence of magnetic field B . (b) A neutron an electron and an alpha particel moving with equal velocities enter a uniform magnetic field going into the plane of the paper as shown. Trace their paths in the field and justify your answer .

DC PANDEY ENGLISH-SOLVED PAPERS 2018-JIPMER
  1. Find R(net) between A and B.

    Text Solution

    |

  2. In the circuit shown in the figure,

    Text Solution

    |

  3. Find V(P)-V(Q) in the circuit shown in figure.

    Text Solution

    |

  4. If a capacitor having capacittance 2F and plate separation of 0.5 cm w...

    Text Solution

    |

  5. Find the capacitance in shown figure

    Text Solution

    |

  6. If minimum deviation = 30^(@), then speed of light in shown prism will...

    Text Solution

    |

  7. A current .I. flows through a metallic wire of radius .r. and the free...

    Text Solution

    |

  8. Find i in shown figure.

    Text Solution

    |

  9. which of these is a fustion reaction ?

    Text Solution

    |

  10. An electron is accelerated through a potential difference V. Write th...

    Text Solution

    |

  11. An atomic power nuclear reactor can deliver 300 MW. The energy release...

    Text Solution

    |

  12. in the fusion reaction ""(1)H^(2)+""(1)H^(2)to ""(2)He^(3) +""(0)N^...

    Text Solution

    |

  13. A prism of crown glass with refracting angle of 5^(@) and mean refract...

    Text Solution

    |

  14. Two slits are separated by a distance of 0.5mm and illuminated with li...

    Text Solution

    |

  15. Calculate the dispersive power for crown glass from the given data m...

    Text Solution

    |

  16. The force of attractions between two charges 8muC and -4muC is 0.2 N. ...

    Text Solution

    |

  17. In a L-C circuit, angular frequency at resonance is omega. What will b...

    Text Solution

    |

  18. If an electron is moving with velocity v produces a magnetic field vec...

    Text Solution

    |

  19. A regular hexagone of side a. A wire of length 24 a is coiled on that ...

    Text Solution

    |

  20. The refractive index of glass is 1.5. The speed of light in glass is

    Text Solution

    |