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In DeltaABC, the value of ("cot"(A)/(2)"...

In `DeltaABC`, the value of `("cot"(A)/(2)"cot"(B)/(2)-1)/("cot"(A)/(2)"cot"(B)/(2))`

A

`(a)/(a+b+c)`

B

`(2c)/(a+b+c)`

C

`(2a)/(a+b+c)`

D

`(2b)/(a+b+c)`

Text Solution

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The correct Answer is:
B
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