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In a triangle ABC, tanA=2, tanB=(3)/(2) ...

In a triangle `ABC, tanA=2, tanB=(3)/(2)` and side `c= sqrt(65)` then circum radius R =

A

65

B

`(65)/(7)`

C

`(65)/(14)`

D

None

Text Solution

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The correct Answer is:
C
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