The resistivity of the material of a wire of length 1 and diameter d and resistance R is given by `rho=(piRd^(2))/(4l)`. The length of the wire I=100.0 cm is measured using a metre scale with a least count of I mm, the diameter d=0.22 cm is measured using an instrument with a least count of 0.01 cm and resistnce R=5.00 ohm is measured with an accuracy of 0.01 ohm. What is the percentage error? Suggest a method to reduced the percentage error.

Explanation

To solve the problem, we need to calculate the percentage error in the resistivity of the wire given the measurements and their respective uncertainties. Here's a step-by-step solution:

### Step 1: Understand the formula for resistivity
The formula for resistivity (ρ) is given by:
\[ \rho = \frac{\pi R d^2}{4l} \]
where:
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