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A physical quantity P is related to four...

A physical quantity P is related to four observably a,b,c and d as follows `P=a^(3)b^(3)//c^(1//2)` d. The percentage errors of measurement in a,b,c and d are 1%, 3%, 4% and 2% respectively. What is the percentage error in the quantity P? If the value of P calculated using the above relation turns out to be 3.763, to what value should you round off the result?

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To find the percentage error in the quantity \( P \) given the relationship \( P = a^3 b^3 \sqrt{c} \, d \), we will follow these steps: ### Step 1: Identify the percentage errors We are given the following percentage errors for the observables: - Percentage error in \( a \) (denoted as \( \delta a/a \)): 1% - Percentage error in \( b \) (denoted as \( \delta b/b \)): 3% - Percentage error in \( c \) (denoted as \( \delta c/c \)): 4% - Percentage error in \( d \) (denoted as \( \delta d/d \)): 2% ...
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