If (2, 3, 5) is one end of a diameter of the sphere `x^2+""y^2+""z^2-6x-12 y-2z""+""20""=""0` , then the coordinates of the other end of the diameter are (1) `(4,""9,-3)` (2) `(4,-3,""3)` (3) `(4,""3,""5)` (4) `(4,""3,-3)`

Explanation

The effective length of the pendulum = length of string + radius of bob
`=88/2+3.53/2=90.0cm`
`g=4pi^(2)1/(T^(2))`
Maximum percentage error in g is
`(Deltag)/gxx100=(Deltal)/lxx100+2xx(DeltaT)/Txx100`
But `T=t/n,(DeltaT)/T=(Deltat)/t`
`(Deltag)/gxx100=(Deltal)/lxx100+2(Deltat)/txx100`
Given `Deltal=0.1cm, l=90.0cm`
`Deltat=0.1s` (least count of stop watch ) `t=19.0s`
`(Deltag)/gxx100=0.1/90xx100+(2xx0.1)/19xx100`
`=0.11% +1.05%=1.15%`
MOre accurate measurement of diameter of bob will not give more accurate value for g. Because length of string is measured only to one decimal point.
Accuracy in g can be increased decreasing error in time period T. For this to must be increased. This means, time for large number of oscillations (say 20, 30 etc). must be measured.