`T_(k) = K ^(3) + 3 ^(k) ,` then find `sum_(k =1) ^( n ) T _(k).`

sum_(k=1)^n k^3=

If n is a positive integer and C_(k)=.^(n)C_(k) then find the value of sum_(k=1)^(n)k^(3)*((C_(k))/(C_(k-1)))^(2)

sum_(k =1)^(n) k(1 + 1/n)^(k -1) =

If Delta_(k) = |(k,1,5),(k^(2),2n +1,2n +1),(k^(3),3n^(2),3n +1)|, " then " sum_(k=1)^(n) Delta_(k) is equal to

If n is a positive integer and C_(k)=""^(n)C_(k) , then the value of sum_(k=1)^(n)k^(3)((C_(k))/(C_(k-1)))^(2) is :

L = lim_ (n rarr oo) (1) / (n ^ (4)) [1.sum_ (k = 1) ^ (n) k + 2 * sum_ (k = 1) ^ (n-1) k + 3 * sum_ (k = 1) ^ (n-2) k + ......... + n.1]

Find the sum, sum_(k=1) ^(20) (1+2+3+.....+k)

Value of L = lim_ (n rarr oo) (1) / (n ^ (4)) [1sum_ (k = 1) ^ (n) k + 2sum_ (k = 1) ^ (n-1) k + 3sum_ ( k = 1) ^ (n-2) k + ...... + n.1] is

Find the sum sum_(k=0)^n ("^nC_k)/(k+1)