Home
Class 12
MATHS
Find the slope of the normal to the curv...

Find the slope of the normal to the curve `x = a cos^(3) theta, y = a sin^(3) theta` at `theta = (pi)/(4)`. A) 0 B) -1 C) 1 D) none of these

Text Solution

Verified by Experts

The correct Answer is:
1
Promotional Banner

Topper's Solved these Questions

  • MODEL TEST PAPER -1

    ICSE|Exercise Section - B|10 Videos
  • MODEL TEST PAPER -1

    ICSE|Exercise Secton - C|11 Videos
  • MODEL TEST PAPER - 8

    ICSE|Exercise Section - C |6 Videos
  • MODEL TEST PAPER -19

    ICSE|Exercise SECTION A|1 Videos

Similar Questions

Explore conceptually related problems

Find the slope of the normal to the curve x=a\ cos^3theta , y=a\ sin^3theta at theta=pi/4 .

Find the equation of normal to the curve x = a cos^(3)theta, y=b sin^(3) theta" at point "'theta'.

Find the slopes of the tangent and the normal to the curve x=a\ cos^3theta,\ \ y=a\ sin^3theta at theta=pi//4

Find the slope of the normal to the curve x=1-asintheta , y=b\ cos^2theta at theta=pi/2 .

Find the equation of normal to the curve x=cos theta, y = sin theta" at point "theta = pi/4*

Find the slopes of the tangent and the normal to the curve x=a(theta-sintheta) , y=a(1+costheta) at theta=-pi//2

Find the slopes of the tangent and the normal to the curve x=a(theta-sintheta),\ \ y=a(1-costheta) at theta=pi//2

Find the length of normal to the curve x=a(theta+sintheta),y=a(1-costheta) at theta=pi/2dot

Find the length of normal to the curve x=a(theta+sintheta),y=a(1-costheta) at theta=pi/2dot

The equation of the normal to the curve x=a\ cos^3theta,\ \ y=a\ sin^3theta at the point theta=pi//4 is (a) x=0 (b) y=0 (c) x=y (d) x+y=a