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A car is moving in a straight line with speed 18 km `h^(-1)` . It is stopped in 5 s by applying the brakes. Find : (i) the speed of car in m `s^(-1)`, (ii) the retardation and (iii) the speed of car after 2 s of applying the brakes.

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Let's solve the problem step by step. ### Given Data: - Initial speed of the car, \( u = 18 \, \text{km/h} \) - Time taken to stop, \( t = 5 \, \text{s} \) - Final speed of the car after stopping, \( v = 0 \, \text{m/s} \) ### Step 1: Convert speed from km/h to m/s ...
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