Home
Class 7
MATHS
A host has arranged 2 bowls of soup for ...

A host has arranged 2 bowls of soup for every three guests, one bowl of main dish for every four guests, and a bowl of dessert for every five guests. There are 134 bowls of food at the party. Find the number of guests at the party.

Text Solution

Verified by Experts

The correct Answer is:
120
Promotional Banner

Topper's Solved these Questions

  • SIMPLE LINEAR EQUATIONS

    ICSE|Exercise Revision Exercise |42 Videos

  • SIMPLE LINEAR EQUATIONS

    ICSE|Exercise Challenge |1 Videos

  • SIMPLE LINEAR EQUATIONS

    ICSE|Exercise Exercise 7.2|17 Videos

  • SIMPLE INTEREST

    ICSE|Exercise Challenge|2 Videos

  • SPEED ,DISTANCE AND TIME

    ICSE|Exercise EXERCISE 12|26 Videos

Similar Questions

Explore conceptually related problems

In a certain party, there is a bowl of soup for every two guests, a bowl of rice for every three guests, and a bowl of dessert for every four guests. If in all there were 65 bowls of food, how many guests were there in the party?

Every two persons shakes hands with each other in a party and the total number of handis 66. The number of guests in the party is

In a group of 40 guests at a party. (1)/(5) of the total number of guests opted for tomato soup, (1)/(4) of the guests chose to have vegetable soup, and the rest had fruit juice. Find the number of guests who had: b. vegetable soup

In a group of 40 guests at a party. (1)/(5) of the total number of guests opted for tomato soup, (1)/(4) of the guests chose to have vegetable soup, and the rest had fruit juice. Find the number of guests who had: a. tomato soup

In a group of 40 guests at a party. (1)/(5) of the total number of guests opted for tomato soup, (1)/(4) of the guests chose to have vegetable soup, and the rest had fruit juice. Find the number of guests who had: c. fruit juice

A gentlemen hosts a party of (m+n) guests and places 'm' at one round table and the remaining 'n' at the other round table. Number of ways the guests can be arranged is

There are 2n guests at a dinner party. Supposing that eh master and mistress of the house have fixed seats opposite one another and that there are two specified guests who must not be placed next to one another, show that the number of ways in which the company can be placed is (2n-2)!xx(4n^2-6n+4)dot