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A question paper has 20 questions, the a...

A question paper has 20 questions, the answer to each of which is either true or false. A student scores 3 marks for every correct answer and loses 2 marks for every incorrect answer. If a student scores 25 marks, find the number of questions he answered correctly and the questions he answered incorrectly.

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To solve the problem, we will set up two equations based on the information given in the question. **Step 1: Define Variables** Let: - \( x \) = number of correct answers - \( y \) = number of incorrect answers **Step 2: Set Up the Equations** From the problem, we know: 1. The total number of questions is 20. Therefore, we can write the first equation as: \[ x + y = 20 \quad \text{(Equation 1)} \] 2. The scoring system states that a student earns 3 marks for each correct answer and loses 2 marks for each incorrect answer. If the student scores 25 marks, we can write the second equation as: \[ 3x - 2y = 25 \quad \text{(Equation 2)} \] **Step 3: Solve the First Equation for One Variable** From Equation 1, we can express \( y \) in terms of \( x \): \[ y = 20 - x \quad \text{(Substituting into Equation 1)} \] **Step 4: Substitute into the Second Equation** Now, substitute \( y \) in Equation 2: \[ 3x - 2(20 - x) = 25 \] Expanding this gives: \[ 3x - 40 + 2x = 25 \] Combine like terms: \[ 5x - 40 = 25 \] **Step 5: Solve for \( x \)** Add 40 to both sides: \[ 5x = 65 \] Now, divide by 5: \[ x = 13 \] **Step 6: Find \( y \)** Now that we have \( x \), we can find \( y \) using the first equation: \[ y = 20 - x = 20 - 13 = 7 \] **Final Answer** The student answered: - Correct answers (\( x \)): 13 - Incorrect answers (\( y \)): 7 ---
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