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What happens when a nickel rod is dipped...

What happens when a nickel rod is dipped into a copper sulphate solution ? Justify your answer.
`[E_(Ni^(+2)//Ni)^@=0*25V and E_(Cu^(+2)//Cu)^@=+0*34V]`

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To solve the question of what happens when a nickel rod is dipped into a copper sulfate solution, we can follow these steps: ### Step 1: Understand the Electrochemical Series The electrochemical series ranks metals based on their standard electrode potentials (E°). A higher E° value indicates a greater tendency to be reduced (gain electrons), while a lower E° value indicates a greater tendency to be oxidized (lose electrons). ### Step 2: Identify the Standard Electrode Potentials From the question, we have: - E° for nickel (Ni²⁺/Ni) = -0.25 V ...
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Can a solution of 1 M copper sulphate be stored in a vessel made of nickel metal ? Given that E_(Ni^(+2)//Ni)^(@)=-0.25 volt and E_(Cu^(+2)//Cu)^(@) =+0.34 volt

Can a solution of 1 M ZnSO_(4) be stored in a vessel made of copper ? Given that E_(Zn^(+2)//Zn)^(@) =-0.76V and E_(Cu^(+2)//Cu)^(@)=0.34 V

Cu^(+) ion is not stable in aqueous solution because because of dispropotionation reaction. E^(@) value of disproportionation of Cu^(+) is [E_(Cu^(2+)//Cu^(+))^(@)=+ 0.15 V, E_(Cu^(2+)//Cu)^(@)=0.34 V]

Is it possible to store: (i) Copper sulphate solution in a zinc vessel? (ii) Copper sulphate solution in a silver vessel? (iii) Copper sulphate solution in a gold vessel? Given: E_(Cu^(2+)| Cu )^(0) = + 0.34 volt and E_(Ag^(2+)| Ag )^(0) = 0.80 volt and E_(Au^(2+)| Au )^(0) = +1.50 volt

Why blue colour of CuSO_(4) solution gets discharged when zinc rod is dipped in it ? Given, E_(Cu^(+2)//Cu)^(@)=0.34 V and E_(Zn^(+2)//Zn)^(@)=-0.76V

E_(Cu^(2+)//Cu)^(@)=0.34V E_(Cu^(+)//Cu)^(@)=0.522V E_(Cu^(2+)//Cu^(+))^(@)=

E_(Cu^(2+)//Cu)^(@)=0.34V E_(Cu^(+)//Cu)^(@)=0.522V E_(Cu^(2+)//Cu^(+))^(@)=

E_(Cu^(2+)//Cu)^(@) =0.43V E_(Cu^(+)//Cu)^(@)=0.55V E_(Cu^(2+)//Cu^(+))^(@) =

A copper-silver cell is set up. The copper ion concentration in it is 0.10 M. The concentration of silver ions is not known.The cell potential measured is 0.422 V. Determine the concentration of silver ions in the cell. [Given E_(Ag^(+)//Ag)^(@)=0.80,E_(Cu^(2+)//Cu)^(@)=+0.34 V]

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