A ball is released from a height and it reaches the ground in 3 s. If `g=9.8 "m s"^(-2)`, find the value of the height from which the ball was released.

Explanation

To find the height from which the ball was released, we can use the second equation of motion, which is given by:

\[ s = ut + \frac{1}{2} a t^2 \]

Where:
- \( s \) is the distance (height in this case, \( h \)),
- \( u \) is the initial velocity,
- \( t \) is the time taken,
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