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If a=hati+2hatj+3hatk,b=-hati+2hatj+hatk...

If `a=hati+2hatj+3hatk,b=-hati+2hatj+hatk and c=3hati+hatj`, then the unit vector along its resultant is

A

`3hati+5hatj+4hatk`

B

`(3hati+5hatj+4hatk)/(50)`

C

`(3hati+5hatj+4hatk)/(5sqrt(2))`

D

none of these

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The correct Answer is:
To find the unit vector along the resultant of the vectors \( \mathbf{a}, \mathbf{b}, \) and \( \mathbf{c} \), we will follow these steps: ### Step 1: Write down the vectors Given: \[ \mathbf{a} = \hat{i} + 2\hat{j} + 3\hat{k} \] \[ \mathbf{b} = -\hat{i} + 2\hat{j} + \hat{k} \] \[ \mathbf{c} = 3\hat{i} + \hat{j} \] ### Step 2: Calculate the resultant vector \( \mathbf{R} \) The resultant vector \( \mathbf{R} \) is given by: \[ \mathbf{R} = \mathbf{a} + \mathbf{b} + \mathbf{c} \] Calculating the components: - **i-component**: \[ 1 - 1 + 3 = 3 \] - **j-component**: \[ 2 + 2 + 1 = 5 \] - **k-component**: \[ 3 + 1 + 0 = 4 \] Thus, the resultant vector is: \[ \mathbf{R} = 3\hat{i} + 5\hat{j} + 4\hat{k} \] ### Step 3: Calculate the magnitude of the resultant vector \( |\mathbf{R}| \) The magnitude \( |\mathbf{R}| \) is calculated as: \[ |\mathbf{R}| = \sqrt{(3)^2 + (5)^2 + (4)^2} \] Calculating each term: \[ |\mathbf{R}| = \sqrt{9 + 25 + 16} = \sqrt{50} \] ### Step 4: Find the unit vector along \( \mathbf{R} \) The unit vector \( \hat{r} \) along \( \mathbf{R} \) is given by: \[ \hat{r} = \frac{\mathbf{R}}{|\mathbf{R}|} \] Substituting the values: \[ \hat{r} = \frac{3\hat{i} + 5\hat{j} + 4\hat{k}}{\sqrt{50}} = \frac{3\hat{i} + 5\hat{j} + 4\hat{k}}{5\sqrt{2}} \] ### Final Answer Thus, the unit vector along the resultant is: \[ \hat{r} = \frac{3}{5\sqrt{2}} \hat{i} + \frac{5}{5\sqrt{2}} \hat{j} + \frac{4}{5\sqrt{2}} \hat{k} \] ---

To find the unit vector along the resultant of the vectors \( \mathbf{a}, \mathbf{b}, \) and \( \mathbf{c} \), we will follow these steps: ### Step 1: Write down the vectors Given: \[ \mathbf{a} = \hat{i} + 2\hat{j} + 3\hat{k} \] \[ ...
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ARIHANT MATHS ENGLISH-VECTOR ALGEBRA-Exercise (Single Option Correct Type Questions)
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