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Statement -1 (1/2)^7lt(1/3)^4 implies ...

Statement -1 `(1/2)^7lt(1/3)^4`
`implies 7log(1/2)lt4log(1/3)implies7lt4`
Statement-2 If `axltay`, where `alt0`,x,`ygt0`, then `xgty`.
(a) Statement-1 is true, Statement-2 is true, Statement-2 is a correct explanation for Statement-1
Statement-1 is true, Statement-2 is true, Statement-2 is not a correct explanation for Statement -1
(c) Statement -1 is true, Statement -2 is false
(d) Statement -1 is false, Statement -2 is true.

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze the two statements provided and determine their truth values. ### Step 1: Analyze Statement 1 The first statement is: \[ \left(\frac{1}{2}\right)^7 < \left(\frac{1}{3}\right)^4 \] To check if this statement is true, we can calculate both sides: - Calculate \(\left(\frac{1}{2}\right)^7\): \[ \left(\frac{1}{2}\right)^7 = \frac{1}{128} \] - Calculate \(\left(\frac{1}{3}\right)^4\): \[ \left(\frac{1}{3}\right)^4 = \frac{1}{81} \] Now, we compare \(\frac{1}{128}\) and \(\frac{1}{81}\): Since \(128 > 81\), we have: \[ \frac{1}{128} < \frac{1}{81} \] Thus, Statement 1 is **true**. ### Step 2: Logarithmic Implication The statement also claims: \[ 7 \log\left(\frac{1}{2}\right) < 4 \log\left(\frac{1}{3}\right) \] Using the property of logarithms that states \(\log(a^b) = b \log(a)\), we can rewrite the logarithms: - \(\log\left(\frac{1}{2}\right) = \log(1) - \log(2) = -\log(2)\) - \(\log\left(\frac{1}{3}\right) = \log(1) - \log(3) = -\log(3)\) Thus, we have: \[ 7(-\log(2)) < 4(-\log(3)) \] This simplifies to: \[ -7\log(2) < -4\log(3) \] Multiplying both sides by -1 (which reverses the inequality): \[ 7\log(2) > 4\log(3) \] This does not imply \(7 < 4\). Therefore, the implication in Statement 1 is **false**. ### Step 3: Analyze Statement 2 The second statement is: "If \(ax < ay\) where \(a < 0\), \(x, y > 0\), then \(x > y\)." To analyze this, we can rearrange the inequality: \[ ax < ay \implies a(x - y) < 0 \] Since \(a < 0\), for the product \(a(x - y)\) to be less than 0, \(x - y\) must be greater than 0. Thus: \[ x - y > 0 \implies x > y \] This confirms that Statement 2 is **true**. ### Conclusion - Statement 1 is **false**. - Statement 2 is **true**. Thus, the correct answer is: **(d) Statement 1 is false, Statement 2 is true.**
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