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If `alpha and beta ` are the solution of ` a cos theta + b sin theta = c`, then

A

`sin alpha + sin beta =(2bc)/(a^(2)+b^(2)) `

B

`sin alpha + sin beta =(c^(2)-a^(2))/(a^(2)+b^(2)) `

C

`sin alpha + sin beta =(2ac)/(b^(2)+c^(2)) `

D

`sin alpha + sin beta =(c)/(a^(2)+b^(2))`

Text Solution

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The correct Answer is:
A, B
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