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Let g(x) be a function defined on[-1,1]d...

Let `g(x)` be a function defined on`[-1,1]dot` If the area of the equilateral triangle with two of its vertices at `(0,0)a n d(x ,g(x))` is `(sqrt(3))/4` , then the function `g(x)` is `g(x)=+-sqrt(1-x^2)` `g(x)=sqrt(1-x^2)` `g(x)=-sqrt(1-x^2)` `g(x)=sqrt(1+x^2)`

A

`g(x)=pm sqrt(1-x^(2))`

B

`g(x)=sqrt(1-x^(2))`

C

`g(x)=-sqrt(1-x^(2))`

D

`g(x)=sqrt(1+x^(2))`

Text Solution

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The correct Answer is:
A
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