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The period of the function f(x)=Sin(x +3...

The period of the function `f(x)=Sin(x +3-[x+3]) `where [] denotes the greatest integer function

A

`2pi+3`

B

`2pi`

C

1

D

4

Text Solution

AI Generated Solution

The correct Answer is:
To find the period of the function \( f(x) = \sin(x + 3 - [x + 3]) \), where \( [ \cdot ] \) denotes the greatest integer function, we can follow these steps: ### Step 1: Simplify the function using the greatest integer function The expression \( x + 3 - [x + 3] \) represents the fractional part of \( x + 3 \). We can denote the fractional part of a number \( y \) as \( \{y\} = y - [y] \). Thus, we can rewrite the function as: \[ f(x) = \sin(\{x + 3\}) \] ### Step 2: Understand the properties of the fractional part function The fractional part function \( \{x + 3\} \) is periodic with a period of 1. This means: \[ \{x + 3\} = \{(x + 1) + 3\} = \{x + 3 + 1\} = \{x + 4\} \] Thus, we can conclude that: \[ \{x + 3\} = \{x\} \quad \text{(since adding an integer does not change the fractional part)} \] ### Step 3: Substitute back into the function Now, we can rewrite the function as: \[ f(x) = \sin(\{x\}) \] ### Step 4: Determine the period of the sine function The function \( \sin(\{x\}) \) inherits the periodicity of the fractional part function. Since \( \{x\} \) is periodic with period 1, \( f(x) \) will also be periodic with period 1. ### Conclusion Therefore, the period of the function \( f(x) = \sin(x + 3 - [x + 3]) \) is: \[ \text{Period} = 1 \] ---
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