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If `f(x)` is a function `f:R-> R`, we say `f(x)` has property I. If `f(f(x)) =x` for all real numbers x. II. `f(-f(x))=-x` for all real numbers x. How many linear functions, have both property I and Il ?

A

0

B

2

C

3

D

Infinite

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The correct Answer is:
To solve the problem, we need to find the linear functions \( f(x) \) that satisfy the two given properties: 1. \( f(f(x)) = x \) for all real numbers \( x \). 2. \( f(-f(x)) = -x \) for all real numbers \( x \). ### Step 1: Assume the form of the linear function Let’s assume that \( f(x) \) is a linear function of the form: \[ f(x) = ax + b \] where \( a \) and \( b \) are constants. ### Step 2: Apply the first property Now, we apply the first property \( f(f(x)) = x \): \[ f(f(x)) = f(ax + b) = a(ax + b) + b = a^2x + ab + b \] Setting this equal to \( x \): \[ a^2x + ab + b = x \] This gives us two equations by comparing coefficients: 1. \( a^2 = 1 \) 2. \( ab + b = 0 \) ### Step 3: Solve the first set of equations From the first equation \( a^2 = 1 \), we find: \[ a = 1 \quad \text{or} \quad a = -1 \] Now, we will analyze each case for \( a \). ### Case 1: \( a = 1 \) Substituting \( a = 1 \) into the second equation: \[ 1 \cdot b + b = 0 \implies 2b = 0 \implies b = 0 \] Thus, one possible function is: \[ f(x) = 1 \cdot x + 0 = x \] ### Case 2: \( a = -1 \) Substituting \( a = -1 \) into the second equation: \[ -1 \cdot b + b = 0 \implies -b + b = 0 \implies 0 = 0 \] This does not provide any restriction on \( b \), so \( b \) can be any real number. Thus, another possible function is: \[ f(x) = -1 \cdot x + b = -x + b \] ### Step 4: Apply the second property Now we apply the second property \( f(-f(x)) = -x \): 1. For \( f(x) = x \): \[ f(-f(x)) = f(-x) = -x \quad \text{(This holds true)} \] 2. For \( f(x) = -x + b \): \[ f(-f(x)) = f(-(-x + b)) = f(x - b) = -(x - b) + b = -x + b + b = -x + 2b \] Setting this equal to \( -x \): \[ -x + 2b = -x \implies 2b = 0 \implies b = 0 \] Thus, this function simplifies to: \[ f(x) = -x \] ### Conclusion The two linear functions that satisfy both properties are: 1. \( f(x) = x \) 2. \( f(x) = -x \) Thus, there are **2 linear functions** that have both properties. ### Final Answer The number of linear functions that have both properties I and II is **2**. ---
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