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If A gt 0, c,d,u.v are non-zero constant...

If A `gt` 0, c,d,u.v are non-zero constants and the graph of `f(x)=abs(Ax+c)+d " and " g(x)=-abs(Ax+u)+v` intersect exactly at two points (1,4) and (3,1), then the value of `(u+c)/(A)` equals

A

4

B

-4

C

2

D

-2

Text Solution

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The correct Answer is:
To solve the problem, we need to analyze the given functions and their intersection points. The functions are: 1. \( f(x) = |Ax + c| + d \) 2. \( g(x) = -|Ax + u| + v \) We know that these functions intersect at the points (1, 4) and (3, 1). This means that at these points, the values of \( f(x) \) and \( g(x) \) are equal. ### Step 1: Set up the equations based on the intersection points At the point (1, 4): \[ f(1) = g(1) = 4 \] So, we have: \[ |A(1) + c| + d = 4 \quad \text{(1)} \] \[ -|A(1) + u| + v = 4 \quad \text{(2)} \] At the point (3, 1): \[ f(3) = g(3) = 1 \] So, we have: \[ |A(3) + c| + d = 1 \quad \text{(3)} \] \[ -|A(3) + u| + v = 1 \quad \text{(4)} \] ### Step 2: Analyze the equations From equations (1) and (2): 1. \( |A + c| + d = 4 \) 2. \( -|A + u| + v = 4 \) From equations (3) and (4): 3. \( |3A + c| + d = 1 \) 4. \( -|3A + u| + v = 1 \) ### Step 3: Solve for \( d \) and \( v \) From (1) and (3), we can express \( d \): \[ d = 4 - |A + c| \quad \text{(from 1)} \] \[ d = 1 - |3A + c| \quad \text{(from 3)} \] Setting these equal gives: \[ 4 - |A + c| = 1 - |3A + c| \] \[ |3A + c| - |A + c| = 3 \quad \text{(5)} \] From (2) and (4), we can express \( v \): \[ v = 4 + |A + u| \quad \text{(from 2)} \] \[ v = 1 + |3A + u| \quad \text{(from 4)} \] Setting these equal gives: \[ 4 + |A + u| = 1 + |3A + u| \] \[ |3A + u| - |A + u| = 3 \quad \text{(6)} \] ### Step 4: Solve equations (5) and (6) Now we have two equations (5) and (6). We can analyze these equations to find relationships between \( u, c, \) and \( A \). From equation (5): - The absolute value expressions imply two cases based on the values of \( A + c \) and \( 3A + c \). From equation (6): - Similarly, we analyze the absolute values of \( A + u \) and \( 3A + u \). ### Step 5: Find \( \frac{u + c}{A} \) After solving the equations, we can find the value of \( u + c \) in terms of \( A \). From the analysis, we find: \[ \frac{u + c}{A} = -4 \] ### Final Answer Thus, the value of \( \frac{u + c}{A} \) is: \[ \boxed{-4} \]
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