Home
Class 12
MATHS
Equation of a line which is tangent to b...

Equation of a line which is tangent to both the curve `y=x^(2)+1 and y=-x^(2)` is

A

`y=sqrt2x+(1)/(2)`

B

`y=sqrt2 x-(1)/(2)`

C

`y=-sqrt2x+(1)/(2)`

D

`y-sqrt2x-(1)/(2)`

Text Solution

Verified by Experts

The correct Answer is:
A, C
Promotional Banner

Topper's Solved these Questions

  • DY / DX AS A RATE MEASURER AND TANGENTS, NORMALS

    ARIHANT MATHS ENGLISH|Exercise Exercise (Statement I And Ii Type Questions)|7 Videos
  • DY / DX AS A RATE MEASURER AND TANGENTS, NORMALS

    ARIHANT MATHS ENGLISH|Exercise Exercise (Passage Based Questions)|8 Videos
  • DY / DX AS A RATE MEASURER AND TANGENTS, NORMALS

    ARIHANT MATHS ENGLISH|Exercise Exercise (Single Option Correct Type Questions)|34 Videos
  • DIFFERENTIATION

    ARIHANT MATHS ENGLISH|Exercise Exercise For Session 10|4 Videos
  • ELLIPSE

    ARIHANT MATHS ENGLISH|Exercise Exercise (Questions Asked In Previous 13 Years Exam)|27 Videos

Similar Questions

Explore conceptually related problems

Equation of a line which is tangent to both the curve y=x^2+1\ a n d\ y=x^2 is y=sqrt(2)x+1/2 (b) y=sqrt(2)x-1/2 y=-sqrt(2)x+1/2 (d) y=-sqrt(2)x-1/2

Find the equation of all straight lines which are tangent to curve y=(1)/(x-1) and which are parallel to the line x+y =0.

Find the equations of all lines having slope 0 which are tangent to the curve y=1/(x^2-2x+3) .

The equation of the tangent to the curve y = e^(2x) at (0,1) is

The equation of common tangent of the curve x^(2) + 4y^(2) = 8 and y^(2) =4x are

The sum of the slopes of the lines tangent to both the circles x^2+y^2=1 and (x-6)^2+y^2=4 is________

Does there exists line/lines which is/are tangent to the curve y=sinx \ a t(x_1, y_1) and normal to the curve at (x_2, y_2)?

Does there exists line/lines which is/are tangent to the curve y=sinx at (x_1, y_1) and normal to the curve at (x_2, y_2)?

The equation of the straight lines which are both tangent and normal to the curve 27x^(2)=4y^(3) are

The equation of the tangents at the origin to the curve y^2=x^2(1+x) are