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A body cools from 60^(@)C to 40^(@)C in ...

A body cools from `60^(@)C` to `40^(@)C` in 7 minutes. Temperature of surrounding is `10^(@)C`. After next 7 minutes what will be its temperature ? During whole process Newton's law of cooling is obeyed.

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To solve the problem, we will use Newton's Law of Cooling, which states that the rate of change of temperature of an object is proportional to the difference between its temperature and the ambient temperature. ### Step-by-step Solution: 1. **Identify the Given Values:** - Initial temperature of the body, \( T_1 = 60^\circ C \) - Final temperature of the body after 7 minutes, \( T_2 = 40^\circ C \) - Surrounding temperature, \( T_s = 10^\circ C \) ...
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