Home
Class 12
MATHS
Let a, b,c are respectively the sines an...

Let a, b,c are respectively the sines and p, q, r are respectively the consines of `alpha, alpha+(2pi)/(3) and alpha+(4pi)/(3)`, then :
Q. The value of `(qc-rb)` is :

A

0

B

`-(sqrt(3))/(2)`

C

`(sqrt(3))/(2)`

D

depends on `alpha`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the value of \( qc - rb \) where: - \( a = \sin(\alpha) \) - \( b = \sin\left(\alpha + \frac{2\pi}{3}\right) \) - \( c = \sin\left(\alpha + \frac{4\pi}{3}\right) \) - \( p = \cos(\alpha) \) - \( q = \cos\left(\alpha + \frac{2\pi}{3}\right) \) - \( r = \cos\left(\alpha + \frac{4\pi}{3}\right) \) ### Step 1: Write down the expressions for \( qc \) and \( rb \) We need to calculate: \[ qc - rb = q \cdot c - r \cdot b \] ### Step 2: Substitute the values of \( q, c, r, \) and \( b \) Substituting the values: \[ qc = \cos\left(\alpha + \frac{2\pi}{3}\right) \cdot \sin\left(\alpha + \frac{4\pi}{3}\right) \] \[ rb = \cos\left(\alpha + \frac{4\pi}{3}\right) \cdot \sin\left(\alpha + \frac{2\pi}{3}\right) \] ### Step 3: Use the sine subtraction formula Notice that: \[ qc - rb = \cos\left(\alpha + \frac{2\pi}{3}\right) \cdot \sin\left(\alpha + \frac{4\pi}{3}\right) - \cos\left(\alpha + \frac{4\pi}{3}\right) \cdot \sin\left(\alpha + \frac{2\pi}{3}\right) \] This expression can be simplified using the sine subtraction formula: \[ \sin(A - B) = \sin A \cos B - \cos A \sin B \] Here, let \( A = \alpha + \frac{4\pi}{3} \) and \( B = \alpha + \frac{2\pi}{3} \). Thus, we have: \[ qc - rb = \sin\left(\left(\alpha + \frac{4\pi}{3}\right) - \left(\alpha + \frac{2\pi}{3}\right)\right) \] ### Step 4: Simplify the angle Now, simplifying the angle: \[ \left(\alpha + \frac{4\pi}{3}\right) - \left(\alpha + \frac{2\pi}{3}\right) = \frac{4\pi}{3} - \frac{2\pi}{3} = \frac{2\pi}{3} \] ### Step 5: Calculate \( \sin\left(\frac{2\pi}{3}\right) \) Now we find: \[ qc - rb = \sin\left(\frac{2\pi}{3}\right) \] Using the sine value: \[ \sin\left(\frac{2\pi}{3}\right) = \sin\left(\pi - \frac{\pi}{3}\right) = \sin\left(\frac{\pi}{3}\right) = \frac{\sqrt{3}}{2} \] ### Final Answer Thus, the value of \( qc - rb \) is: \[ \frac{\sqrt{3}}{2} \] ---
Promotional Banner

Topper's Solved these Questions

  • COMPOUND ANGLES

    VIKAS GUPTA (BLACK BOOK) ENGLISH|Exercise Exercise-4 : Matching Type Problems|5 Videos
  • COMPOUND ANGLES

    VIKAS GUPTA (BLACK BOOK) ENGLISH|Exercise Exercise-5 : Subjective Type Problems|31 Videos
  • COMPOUND ANGLES

    VIKAS GUPTA (BLACK BOOK) ENGLISH|Exercise Exercise-2 : One or More than One Answer is/are Correct|26 Videos
  • COMPLEX NUMBERS

    VIKAS GUPTA (BLACK BOOK) ENGLISH|Exercise EXERCISE-5 : SUBJECTIVE TYPE PROBLEMS|8 Videos
  • CONTINUITY, DIFFERENTIABILITY AND DIFFERENTIATION

    VIKAS GUPTA (BLACK BOOK) ENGLISH|Exercise EXERCISE (SUBJECTIVE TYPE PROBLEMS)|24 Videos

Similar Questions

Explore conceptually related problems

Let a, b,c are respectively the sines and p, q, r are respectively the consines of alpha, alpha+(2pi)/(3) and alpha+(4pi)/(3) , then : Q. The value of (a+b+c) is :

Let a, b,c are respectively the sines and p, q, r are respectively the consines of alpha, alpha+(2pi)/(3) and alpha+(4pi)/(3) , then : Q. The value of (ab+bc+ca) is :

Show that 4 sin alpha.sin (alpha + pi/3) sin (alpha + 2pi/3) = sin 3alpha

Verify : "cosec "alpha=1+cot^(2)alpha" if "alpha=(pi)/(3) .

If 2 sin 2alpha= | tan beta+ cot beta |alpha,beta, in((pi)/(2),pi) , then the value of alpha+beta is

show that : sin^2 alpha + sin^2(alpha +( 2pi)/n) +sin^2(alpha +( 4pi)/n) + ..... n terms = n/2

Let f(theta)=cottheta/(1+cottheta) and alpha+beta=(5pi)/4 then the value f(alpha)f (beta) is

If the roots of the equation px ^(2) +qx + r=0, where 2p , q, 2r are in G.P, are of the form alpha ^(2), 4 alpha-4. Then the value of 2p + 4q+7r is :

Let alpha and beta be such that pi < alpha-beta<3pi, If sinalpha+sinbeta=-(21)/(65) and cosalpha+cosbeta=-(27)/(65) , then the value of cos(alpha-beta)/2 is (a) -3/(sqrt(130)) (b) 3/(sqrt(130)) (c) 6/(25) (d) 6/(65)

If 0 lt alpha lt (pi)/(3) , then prove that alpha (sec alpha) lt (2pi)/(3).