In van Arkel method, if `I_(2)` is introduced at 1700 K over impure metal, the product will be :

Options

A. Iodide of the metal
B. No reaction takes place
C. Impurities react with iodine
D. None of these

Answer

To solve the problem regarding the van Arkel method and the introduction of iodine at 1700 K over impure metal, we can follow these steps:

### Step-by-Step Solution:

1. **Understanding the Van Arkel Method**:
The van Arkel method is a process used for the purification of certain metals, particularly titanium. It involves the reaction of the impure metal with iodine to form a volatile metal iodide.

2. **Temperature Consideration**:
The question states that iodine is introduced at a temperature of 1700 K. This temperature is suitable for the reaction to occur, as it is high enough to facilitate the formation of the metal iodide.

3. **Reaction with Iodine**:
When iodine (I₂) is introduced to impure titanium (Ti), a reaction occurs where titanium reacts with iodine to form titanium iodide (TiI₄). The reaction can be represented as:
\[ \text{Ti (impure) + 2 I}_2 \rightarrow \text{TiI}_4 \text{ (volatile)} \]

4. **Formation of Volatile Product**:
The titanium iodide (TiI₄) formed is a volatile compound. This means that it can easily vaporize and separate from the impurities that remain solid.

5. **Separation of Impurities**:
As the titanium iodide vaporizes, the impurities in the impure titanium do not react with iodine and remain behind as solid residues.

6. **Conclusion**:
The main product of the reaction when iodine is introduced to impure titanium at 1700 K is titanium iodide (TiI₄). Therefore, the correct answer to the question is that the product will be the iodide of the metal.

### Final Answer:
The product will be titanium iodide (TiI₄).

---